Optimal. Leaf size=154 \[ \frac{\text{EllipticF}\left (\frac{1}{2} (c+d x),2\right )}{d \left (a^2-b^2\right )}+\frac{a E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{b d \left (a^2-b^2\right )}+\frac{\left (a^2-3 b^2\right ) \Pi \left (\frac{2 a}{a+b};\left .\frac{1}{2} (c+d x)\right |2\right )}{b d (a-b) (a+b)^2}-\frac{a^2 \sin (c+d x)}{b d \left (a^2-b^2\right ) \sqrt{\cos (c+d x)} (a+b \sec (c+d x))} \]
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Rubi [A] time = 0.445169, antiderivative size = 154, normalized size of antiderivative = 1., number of steps used = 10, number of rules used = 9, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.391, Rules used = {4264, 3845, 4106, 3849, 2805, 3787, 3771, 2639, 2641} \[ \frac{F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{d \left (a^2-b^2\right )}+\frac{a E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{b d \left (a^2-b^2\right )}+\frac{\left (a^2-3 b^2\right ) \Pi \left (\frac{2 a}{a+b};\left .\frac{1}{2} (c+d x)\right |2\right )}{b d (a-b) (a+b)^2}-\frac{a^2 \sin (c+d x)}{b d \left (a^2-b^2\right ) \sqrt{\cos (c+d x)} (a+b \sec (c+d x))} \]
Antiderivative was successfully verified.
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Rule 4264
Rule 3845
Rule 4106
Rule 3849
Rule 2805
Rule 3787
Rule 3771
Rule 2639
Rule 2641
Rubi steps
\begin{align*} \int \frac{1}{\cos ^{\frac{5}{2}}(c+d x) (a+b \sec (c+d x))^2} \, dx &=\left (\sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{\sec ^{\frac{5}{2}}(c+d x)}{(a+b \sec (c+d x))^2} \, dx\\ &=-\frac{a^2 \sin (c+d x)}{b \left (a^2-b^2\right ) d \sqrt{\cos (c+d x)} (a+b \sec (c+d x))}-\frac{\left (\sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{-\frac{a^2}{2}-a b \sec (c+d x)-\frac{1}{2} \left (a^2-2 b^2\right ) \sec ^2(c+d x)}{\sqrt{\sec (c+d x)} (a+b \sec (c+d x))} \, dx}{b \left (a^2-b^2\right )}\\ &=-\frac{a^2 \sin (c+d x)}{b \left (a^2-b^2\right ) d \sqrt{\cos (c+d x)} (a+b \sec (c+d x))}-\frac{\left (\sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{-\frac{a^3}{2}-\frac{1}{2} a^2 b \sec (c+d x)}{\sqrt{\sec (c+d x)}} \, dx}{a^2 b \left (a^2-b^2\right )}-\frac{\left (\left (-a^2+3 b^2\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{\sec ^{\frac{3}{2}}(c+d x)}{a+b \sec (c+d x)} \, dx}{2 b \left (a^2-b^2\right )}\\ &=-\frac{a^2 \sin (c+d x)}{b \left (a^2-b^2\right ) d \sqrt{\cos (c+d x)} (a+b \sec (c+d x))}+\frac{\left (a^2-3 b^2\right ) \int \frac{1}{\sqrt{\cos (c+d x)} (b+a \cos (c+d x))} \, dx}{2 b \left (a^2-b^2\right )}+\frac{\left (\sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \sqrt{\sec (c+d x)} \, dx}{2 \left (a^2-b^2\right )}+\frac{\left (a \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{1}{\sqrt{\sec (c+d x)}} \, dx}{2 b \left (a^2-b^2\right )}\\ &=\frac{\left (a^2-3 b^2\right ) \Pi \left (\frac{2 a}{a+b};\left .\frac{1}{2} (c+d x)\right |2\right )}{(a-b) b (a+b)^2 d}-\frac{a^2 \sin (c+d x)}{b \left (a^2-b^2\right ) d \sqrt{\cos (c+d x)} (a+b \sec (c+d x))}+\frac{\int \frac{1}{\sqrt{\cos (c+d x)}} \, dx}{2 \left (a^2-b^2\right )}+\frac{a \int \sqrt{\cos (c+d x)} \, dx}{2 b \left (a^2-b^2\right )}\\ &=\frac{a E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{b \left (a^2-b^2\right ) d}+\frac{F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{\left (a^2-b^2\right ) d}+\frac{\left (a^2-3 b^2\right ) \Pi \left (\frac{2 a}{a+b};\left .\frac{1}{2} (c+d x)\right |2\right )}{(a-b) b (a+b)^2 d}-\frac{a^2 \sin (c+d x)}{b \left (a^2-b^2\right ) d \sqrt{\cos (c+d x)} (a+b \sec (c+d x))}\\ \end{align*}
Mathematica [A] time = 3.26628, size = 242, normalized size = 1.57 \[ \frac{\frac{\frac{2 \sin (c+d x) \left (2 b (a+b) \text{EllipticF}\left (\sin ^{-1}\left (\sqrt{\cos (c+d x)}\right ),-1\right )-\left (a^2-2 b^2\right ) \Pi \left (-\frac{a}{b};\left .-\sin ^{-1}\left (\sqrt{\cos (c+d x)}\right )\right |-1\right )-2 a b E\left (\left .\sin ^{-1}\left (\sqrt{\cos (c+d x)}\right )\right |-1\right )\right )}{b \sqrt{\sin ^2(c+d x)}}+4 b \left (2 \text{EllipticF}\left (\frac{1}{2} (c+d x),2\right )-\frac{2 b \Pi \left (\frac{2 a}{a+b};\left .\frac{1}{2} (c+d x)\right |2\right )}{a+b}\right )+\frac{2 \left (3 a^2-4 b^2\right ) \Pi \left (\frac{2 a}{a+b};\left .\frac{1}{2} (c+d x)\right |2\right )}{a+b}}{(a-b) (a+b)}+\frac{4 a^2 \sin (c+d x) \sqrt{\cos (c+d x)}}{\left (b^2-a^2\right ) (a \cos (c+d x)+b)}}{4 b d} \]
Antiderivative was successfully verified.
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Maple [B] time = 3.063, size = 608, normalized size = 4. \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (b \sec \left (d x + c\right ) + a\right )}^{2} \cos \left (d x + c\right )^{\frac{5}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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